X=p^2-120p+3600

Solution for X=p^2-120p+3600 equation:

X=X^2-120X+3600

We move all terms to the left:

X-(X^2-120X+3600)=0

We get rid of parentheses

-X^2+X+120X-3600=0

We add all the numbers together, and all the variables

-1X^2+121X-3600=0

a = -1; b = 121; c = -3600;
Δ = b2-4ac
Δ = 1212-4·(-1)·(-3600)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-\sqrt{241}}{2*-1}=\frac{-121-\sqrt{241}}{-2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+\sqrt{241}}{2*-1}=\frac{-121+\sqrt{241}}{-2}
$